Решебник по математике 6 класс Ерина Никольский рабочая тетрадь Часть 1, 2 Часть 1 | Страница 85

Авторы:
Тип:рабочая тетрадь
Часть:1, 2
Серия:Учебно-методический комплект

Страница 85

\[\mathbf{Страница\ 85.}\]

\[\boxed{\mathbf{2.}}\]

\[\textbf{а)}\ \frac{8}{24} + \frac{3}{6} = \frac{2}{6} + \frac{3}{6} = \frac{5}{6}\]

\[\frac{9}{49} - \frac{1}{7} = \frac{9}{49} - \frac{7}{49} = \frac{2}{49}\]

\[\textbf{б)}\ \frac{1}{7} + \frac{1}{6} = \frac{6}{42} + \frac{7}{42} = \frac{13}{42}\]

\[\frac{5}{14} - \frac{1}{10} = \frac{25}{70} - \frac{7}{70} = \frac{18}{70} = \frac{9}{35}\]

\[\textbf{в)}\ \frac{15}{48} + \frac{3}{16} = \frac{5}{16} + \frac{3}{16} = \frac{8}{16} = \frac{1}{2}\]

\[\frac{7}{15} + \frac{9}{20} = \frac{28}{60} + \frac{27}{60} = \frac{55}{60} = \frac{11}{12}\]

\[\boxed{\mathbf{3.}}\]

\[\textbf{а)}\ ( - 81) + 16 = - 65\]

\[( - 64) + 95 = 31\]

\[56 + ( - 39) = 17\]

\[48 + ( - 96) = - 48\]

\[( - 47) + ( - 93) = - 140\]

\[\textbf{б)}\ ( - 62) + 14 = - 48\]

\[( - 73) + 100 = 27\]

\[44 + ( - 35) = 9\]

\[23 + ( - 71) = - 48\]

\[( - 26) + ( - 84) = - 110\]

\[\textbf{в)}\ ( - 21) + 16 = - 5\]

\[( - 101) + 200 = 99\]

\[85 + ( - 47) = 38\]

\[56 + ( - 93) = - 37\]

\[( - 37) + ( - 126) = - 163\]

\[\boxed{\mathbf{4.}}\]

\[\textbf{а)}\ - \frac{1}{5} + \left( - \frac{1}{5} \right) = - \frac{2}{5}\]

\[- \frac{3}{7} + \left( - \frac{4}{7} \right) = - \frac{7}{7} = - 1\]

\[- \frac{2}{5} + \left( - \frac{3}{5} \right) = - \frac{5}{5} = - 1\]

\[\textbf{б)} - \frac{2}{9} + \left( - \frac{1}{9} \right) = - \frac{3}{9} = - \frac{1}{3}\]

\[- \frac{10}{13} + \left( - \frac{3}{13} \right) = - \frac{13}{13} = - 1\]

\[- \frac{7}{11} + \left( - \frac{4}{11} \right) = - \frac{11}{11} = - 1\]

\[\textbf{в)} - \frac{4}{13} + \left( - \frac{2}{13} \right) = - \frac{6}{13}\]

\[- \frac{18}{31} + \left( - \frac{13}{31} \right) = - \frac{31}{31} = - 1\]

\[- \frac{11}{17} + \left( - \frac{6}{17} \right) = - \frac{17}{17} = - 1\]

\[\boxed{\mathbf{5.}}\]

\[\textbf{а)} - \frac{1}{7} + \frac{3}{7} = \frac{2}{7}\]

\[\frac{1}{6} + \left( - \frac{5}{6} \right) = - \frac{4}{6} = - \frac{2}{3}\]

\[\frac{5}{8} + \left( - \frac{7}{8} \right) = - \frac{2}{8} = - \frac{1}{4}\]

\[\textbf{б)} - \frac{3}{10} + \frac{7}{10} = \frac{4}{10} = \frac{2}{5}\]

\[\frac{1}{7} + \left( - \frac{4}{7} \right) = - \frac{3}{7}\]

\[\frac{3}{5} + \left( - \frac{4}{5} \right) = - \frac{1}{5}\]

\[\textbf{в)} - \frac{2}{19} + \frac{10}{19} = \frac{8}{19}\]

\[\frac{1}{100} + \left( - \frac{7}{100} \right) = - \frac{6}{100}\]

\[\frac{4}{17} + \left( - \frac{9}{17} \right) = - \frac{5}{17}\]

\[\boxed{\mathbf{6.}}\]

\[\textbf{а)}\ \frac{1}{7} - \frac{3}{7} = - \frac{2}{7}\]

\[\frac{2}{5} - \frac{4}{5} = - \frac{2}{5}\]

\[\frac{3}{7} - \frac{5}{7} = - \frac{2}{7}\]

\[\textbf{б)}\ \frac{1}{4} - \frac{3}{4} = - \frac{2}{4}\]

\[\frac{3}{10} - \frac{7}{10} = - \frac{4}{10} = - \frac{2}{5}\]

\[\frac{5}{17} - \frac{8}{17} = - \frac{3}{17}\]

\[\textbf{в)}\ \frac{1}{8} - \frac{5}{8} = - \frac{4}{8} = - \frac{1}{2}\]

\[\frac{4}{7} - \frac{6}{7} = - \frac{2}{7}\]

\[\frac{5}{21} - \frac{7}{21} = - \frac{2}{21}\]

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