Решебник по математике 5 класс Виленкин Часть 1, 2 Часть 2. Параграф 6. Десятичные дроби Задание 113

\[\boxed{\text{6.11}\text{3}\text{.}}\]

\[\textbf{а)}\ \frac{4}{7} + x = \frac{5}{7}\]

\[x = \frac{5}{7} - \frac{4}{7}\]

\[x = \frac{1}{7}\text{.\ }\]

\[Ответ:\ \frac{1}{7}\text{.\ }\]

\[\textbf{б)}\ m - \frac{2}{9} = \frac{5}{9}\]

\[m = \frac{5}{9} + \frac{2}{9}\]

\[m = \frac{7}{9}\text{.\ }\]

\[Ответ:\ \frac{7}{9}\text{.\ }\]

\[\textbf{в)}\ \frac{13}{15} - z = \frac{7}{45}\]

\[z = \frac{13}{15} - \frac{7}{45}\]

\[z = \frac{39}{45} - \frac{7}{45}\]

\[z = \frac{32}{45}\text{.\ }\]

\[Ответ:\ \frac{32}{45}\text{.\ }\]

\[\textbf{г)}\ n + \frac{3}{5} = 1\]

\[n = 1 - \frac{3}{5}\]

\[n = \frac{2}{5}\text{.\ }\]

\[Ответ:\ \frac{2}{5}\text{.\ \ \ }\]