Решебник по математике 5 класс Виленкин Часть 1, 2 Часть 2. Параграф 5. Обыкновенные дроби Задание 334

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\[\textbf{а)}\ \frac{33}{99} = \frac{3 \cdot 11}{3 \cdot 3 \cdot 11} = \frac{1}{3}\ \]

\[\frac{150}{125} = \frac{5 \cdot 5 \cdot 6}{5 \cdot 5 \cdot 5} = \frac{6}{5}\ \]

\[\frac{25}{100} = \frac{5 \cdot 5}{5 \cdot 5 \cdot 4} = \frac{1}{4}\ \]

\[\frac{14}{210} = \frac{2 \cdot 7}{2 \cdot 3 \cdot 5 \cdot 7} = \frac{1}{3 \cdot 5} = \frac{1}{15}\ \]

\[\frac{150}{1000} = \frac{5 \cdot 5 \cdot 6}{5 \cdot 5 \cdot 5 \cdot 8} = \frac{6}{5 \cdot 8} =\]

\[= \frac{2 \cdot 3}{5 \cdot 2 \cdot 4} = \frac{3}{5 \cdot 4} = \frac{3}{20}\ \]

\[\frac{1000}{2500} = \frac{10 \cdot 100}{25 \cdot 100} = \frac{10}{25} = \frac{2 \cdot 5}{5 \cdot 5} =\]

\[= \frac{2}{5}\ \]

\[\frac{264}{148} = \frac{8 \cdot 33}{4 \cdot 37} = \frac{2 \cdot 4 \cdot 33}{4 \cdot 37} =\]

\[= \frac{2 \cdot 33}{37} = \frac{66}{37}\]

\[\textbf{б)}\ \frac{45}{630} = \frac{5 \cdot 9}{9 \cdot 70} = \frac{5}{70} = \frac{5}{14 \cdot 5} =\]

\[= \frac{1}{14}\ \]

\[\frac{30}{64} = \frac{5 \cdot 6}{8 \cdot 8} = \frac{5 \cdot 2 \cdot 3}{2 \cdot 4 \cdot 8} = \frac{5 \cdot 3}{4 \cdot 8} =\]

\[= \frac{15}{32}\ \]

\[\frac{125}{500} = \frac{5 \cdot 5 \cdot 5}{25 \cdot 20} = \frac{5 \cdot 5 \cdot 5}{5 \cdot 5 \cdot 5 \cdot 4} = \frac{1}{4}\ \]

\[\frac{7}{217} = \frac{7}{7 \cdot 31} = \frac{1}{31}\ \]

\[\frac{12}{600} = \frac{2 \cdot 6}{6 \cdot 100} = \frac{2}{100} = \frac{2}{2 \cdot 50} =\]

\[= \frac{1}{50}\ \]

\[\frac{75}{300} = \frac{5 \cdot 5 \cdot 3}{3 \cdot 100} = \frac{5 \cdot 5}{100} =\]

\[= \frac{5 \cdot 5}{5 \cdot 5 \cdot 4} = \frac{1}{4}\text{\ \ }\]

\[\frac{140}{210} = \frac{14 \cdot 10}{21 \cdot 10} = \frac{14}{21} = \frac{2 \cdot 7}{3 \cdot 7} = \frac{2}{3}\ \]