\[\boxed{\mathbf{3.}\mathbf{362}}\]
Пояснение.
Решение.
\[1)\ a = 17 \cdot 9 + 5 = 153 + 5 =\]
\[= 158.\]
\[2)\ 461 = 27b + 2\]
\[27b = 461 - 2\]
\[27b = 459\]
\[b = 459\ :27\]
\[b = 17.\]
\[В\ учебнике\ скорее\ всего\ \]
\[опечатка.\]
\[Проверка:\]
\[3)\ 258 = 16q + r\]
\[258\ :16 = 16\ (ост.\ 2)\]
\[q = 16;\ \ r = 2.\]