Решебник по математике 5 класс Ткачева ФГОС рабочая тетрадь Часть 1, 2 Часть 1 | Страница 36

\[Страница\ 36.\]

\[17.\ Степень\ с\ натуральным\]

\[\ показателем\]

\[\boxed{\mathbf{1}.}\]

\[\textbf{а)}\ 5^{2}\]

\[\textbf{б)}\ 4^{3}\]

\[\textbf{в)}\ 13^{3}\]

\[\textbf{г)}\ 100^{2}\]

\[\boxed{\mathbf{2}.}\]

\[\textbf{а)}\ 2^{6}\]

\[\textbf{б)}\ 3^{4}\]

\[\textbf{в)}\ a^{6}\]

\[\textbf{г)}\ (x - y)^{3}\]

\[\boxed{\mathbf{3}.}\]

\[\textbf{а)}\ 5^{2} + 6^{2} = 5 \cdot 5 + 6 \cdot 6 =\]

\[= 25 + 36 = 61\]

\[\textbf{б)}\ 3^{2} + 4^{2} = 3 \cdot 3 + 4 \cdot 4 =\]

\[= 9 + 16 = 25\]

\[\textbf{в)}\ 2^{3} + 3^{3} = 2 \cdot 2 \cdot 2 +\]

\[+ 3 \cdot 3 \cdot 3 = 8 + 27 = 35\]

\[\textbf{г)}\ 4^{3} + 8^{2} = 64 + 64 = 128\]

\[\textbf{д)}\ 7^{2} - 3^{3} = 49 - 27 = 22\ \]

\[\boxed{\mathbf{4}.}\]

\[\textbf{а)}\ 3 + 2^{4} = 3 + 16 = 19\]

\[\textbf{б)}\ 5^{2} - 3^{2} = 25 - 9 = 16\]

\[\textbf{в)}\ 2 \cdot 4^{3} - 7^{2} = 2 \cdot 64 - 49\]

\[= = 128 - 49 = 79\]

\[\textbf{г)}\ 3 \cdot 6^{2} + 8^{2}\ :2^{5} = 3 \cdot 36 +\]

\[+ 64\ :32 = 108 + 2 = 110\]

\[\boxed{\mathbf{5}.}\]

\[\textbf{а)}\ 34\ 069 = 3 \cdot 10^{4} + 4 \cdot 10^{3} +\]

\[+ 6 \cdot 10^{1} + 9\]

\[\textbf{б)}\ 506\ 781 = 5 \cdot 10^{5} + 6 \cdot 10^{3} +\]

\[+ 7 \cdot 10^{2} + 8 \cdot 10^{1} + 1\]