Решебник по математике 5 класс Ткачева рабочая тетрадь | Страница 64

Авторы:
Год:2020-2021
Тип:рабочая тетрадь

Страница 64

\[\boxed{\mathbf{1.}}\]

\[1)\ \frac{2}{3} = \frac{2 \cdot 5}{3 \cdot 5} = \frac{10}{15}\]

\[2)\ \frac{3}{11} = \frac{3 \cdot 4}{11 \cdot 4} = \frac{12}{44}\]

\[3)\ \frac{5}{12} = \frac{5 \cdot 3}{12 \cdot 3} = \frac{15}{36}\]

\[\boxed{\mathbf{2.}}\]

\[1)\ \frac{1}{5} = \frac{3}{15} = \frac{9}{45} = \frac{18}{90}\]

\[2)\ \frac{2}{3} = \frac{4}{6} = \frac{8}{12} = \frac{32}{48}\]

\[\boxed{\mathbf{3.}}\]

\[1)\ \frac{2}{7} = \frac{8}{56}\]

\[\frac{2}{7} = \frac{6}{21}\]

\[\frac{2}{7} = \frac{10}{35}\]

\[2)\ \frac{5^{\backslash 2}}{6} = \frac{10}{12}\]

\[\frac{5^{\backslash 5}}{6} = \frac{25}{30}\]

\[\frac{5^{\backslash 3}}{6} = \frac{15}{18}\]

\[\boxed{\mathbf{4.}}\]

\[1)\ \frac{10}{45} = \frac{10\ :5}{45\ :5} = \frac{2}{9}\]

\[2)\ \frac{24}{36} = \frac{24\ :6}{36\ :6} = \frac{4}{6}\]

\[3)\ \frac{24}{36} = \frac{24\ :12}{36\ :12} = \frac{2}{3}\]

\[\boxed{\mathbf{5.}}\]

\[1)\ \frac{2}{8} = \frac{1}{4}\]

\[2)\ \frac{15}{20} = \frac{3}{4}\]

\[3)\ \frac{18}{30} = \frac{3}{5}\]

\[4)\ \frac{64}{48} = \frac{4}{3}\]

\[\mathbf{37.\ 2.\ Приведение\ дробей\ к\ общему\ знаменателю}\]

\[\boxed{\mathbf{1.}}\]

\[1)\ \frac{1}{2} = \frac{1 \cdot 36}{2 \cdot 36} = \frac{36}{72}\]

\[2)\ \frac{2}{3} = \frac{2 \cdot 24}{72} = \frac{48}{72}\]

\[3)\ \frac{3^{\backslash 18}}{4} = \frac{3 \cdot 18}{72} = \frac{54}{72}\]

\[4)\ \frac{5^{\backslash 12}}{6} = \frac{5 \cdot 12}{72} = \frac{60}{72}\]

\[5)\ \frac{3^{\backslash 9}}{8} = \frac{3 \cdot 9}{72} = \frac{27}{72}\]

\[6)\ \frac{5^{\backslash 6}}{12} = \frac{5 \cdot 6}{72} = \frac{30}{72}\]

\[7)\ \frac{11^{\backslash 4}}{18} = \frac{11 \cdot 4}{72} = \frac{44}{72}\]

\[8)\ \frac{15^{\backslash 2}}{36} = \frac{15 \cdot 2}{72} = \frac{30}{72}\]

\[\boxed{\mathbf{2.}}\]

\[1)\ \frac{7}{20}\ и\ \frac{4}{35}\]

\[НОК(20,\ 35) = 140\]

\[\frac{7^{\backslash 7}}{20} = \frac{49}{140};\ \ \frac{4^{\backslash 4}}{35} = \frac{16}{140}.\]

\[2)\ \frac{11}{14}\ и\ \frac{11}{42}\]

\[НОК(11,\ 42) = 42\]

\[\frac{11^{\backslash 3}}{14} = \frac{33}{42};\ \ \ \frac{11^{\backslash 1}}{42} = \frac{11}{42}.\]

\[3)\ \frac{13}{12}\ и\ \frac{5}{9}\]

\[НОК(12,\ 9) = 36\]

\[\frac{13^{\backslash 3}}{12} = \frac{39}{36};\ \ \ \frac{5^{\backslash 4}}{9} = \frac{20}{36}.\]


Скачать ответ
Есть ошибка? Сообщи нам!

Решебники по другим предметам