Решебник по математике 5 класс Ерина Виленкин рабочая тетрадь Часть 1, 2 Часть 2 | Страница 30

\[Стр.\ 30.\]

\[32.\ Сложение\ и\ вычитание\ смешанных\ чисел\]

\[\boxed{\mathbf{1.}}\]

\[\textbf{а)}\ 8 = 7\frac{6}{6}\]

\[\textbf{б)}\ 9 = 8\frac{4}{4}\]

\[\textbf{в)}\ 14 = 13\frac{10}{10}\]

\[\textbf{г)}\ 9 = 8\frac{5}{5}\]

\[\textbf{д)}\ 6 = 5\frac{3}{3}\]

\[\textbf{е)}\ 12 = 11\frac{7}{7}\]

\[\textbf{ж)}\ 15 = 14\frac{8}{8}\]

\[\textbf{з)}\ 24 = 23\frac{11}{11}\]

\[\textbf{и)}\ 3 = 2\frac{4}{4}\]

\[к)\ 9 = 8\frac{7}{7}\]

\[л)\ 28 = 27\frac{10}{10}\]

\[м)\ 40 = 39\frac{21}{21}\]

\[\boxed{\mathbf{2.}}\]

\[\textbf{а)}\ 7\frac{2}{3} = 6\frac{5}{3}\]

\[\textbf{б)}\ 15\frac{7}{9} = 14\frac{16}{9}\]

\[\textbf{в)}\ 12\frac{5}{8} = 11\frac{13}{8}\]

\[\textbf{г)}\ 1\frac{6}{10} = \frac{16}{10}\]

\[\textbf{д)}\ 11\frac{2}{7} = 10\frac{9}{7}\]

\[\textbf{е)}\ 16\frac{1}{5} = 15\frac{6}{5}\]

\[\textbf{ж)}\ 3\frac{6}{7} = 2\frac{13}{7}\]

\[\textbf{з)}\ 2\frac{8}{9} = 1\frac{17}{9}\]

\[\textbf{и)}\ 1\frac{1}{7} = \frac{8}{7}\]

\[к)\ 1\frac{3}{5} = \frac{8}{5}\]

\[л)\ 1\frac{4}{9} = \frac{13}{9}\]

\[м)\ 1\frac{9}{100} = \frac{109}{100}\]

\[\boxed{\mathbf{3.}}\]

\[\textbf{а)}\ 7\frac{1}{2} + 4 = (7 + 4) + \frac{1}{2} = 11\frac{1}{2}\]

\[\textbf{б)}\ 7\frac{1}{2} - 4 = (7 - 4) + \frac{1}{2} = 3\frac{1}{2}\]

\[\textbf{в)}\ 13\frac{3}{7} + 5 = (13 + 5) + \frac{3}{7} =\]

\[= 18\frac{3}{7}\]

\[\textbf{г)}\ 2\frac{8}{9} + 19 = (2 + 19) + \frac{8}{9} =\]

\[= 21\frac{8}{9}\]

\[\textbf{д)}\ 37\frac{5}{9} - 9 = (37 - 9) + \frac{5}{9} =\]

\[= 28\frac{5}{9}\]

\[\textbf{е)}\ 4\frac{13}{15} - 4 = (4 - 4) + \frac{13}{15} =\]

\[= \frac{13}{15}\]

\[\textbf{ж)}\ 15\frac{1}{10} - 8 = (15 - 8) + \frac{1}{10} =\]

\[= 7\frac{1}{10}\]

\[\textbf{з)}\ 34\frac{5}{11} + 9 = (34 + 9) + \frac{5}{11} =\]

\[= 43\frac{5}{11}\]