Решебник по математике 5 класс Ерина Виленкин рабочая тетрадь Часть 1, 2 Часть 2 | Страница 22

\[Стр.\ 22.\]

\[\boxed{\mathbf{8.}}\]

\[\textbf{а)}\ \frac{107}{111} - \frac{75}{111} - \frac{12}{111} =\]

\[= \frac{107 - 75 - 12}{111} = \frac{20}{111}\]

\[\textbf{б)}\ \frac{132}{163} - \frac{17}{163} - \frac{75}{163} =\]

\[= \frac{132 - 17 - 75}{163} = \frac{40}{163}\]

\[\textbf{в)}\ \frac{62}{103} - \frac{37}{103} - \frac{15}{103} =\]

\[= \frac{62 - 37 - 15}{103} = \frac{10}{103}\]

\[\textbf{г)}\ \frac{100}{187} - \frac{43}{187} - \frac{37}{187} =\]

\[= \frac{100 - 43 - 37}{187} = \frac{20}{187}\]

\[\boxed{\mathbf{9.}}\]

\[\textbf{а)}\ \frac{17}{179} + \frac{167}{179} - \frac{77}{179} - \frac{67}{179} =\]

\[= \frac{167 - 67 + 17 - 77}{179} = \frac{40}{179}\]

\[\textbf{б)}\ \frac{102}{109} + \frac{18}{109} - \frac{39}{109} - \frac{51}{109} =\]

\[= \frac{102 + 18 - 39 - 51}{109} = \frac{30}{109}\]

\[\textbf{в)}\ \frac{19}{131} + \frac{129}{131} - \frac{49}{131} - \frac{39}{131} =\]

\[= \frac{19 + 129 - 49 - 39}{131} = \frac{60}{131}\]

\[\textbf{г)}\ \frac{61}{153} + \frac{109}{153} - \frac{68}{153} - \frac{2}{153} =\]

\[= \frac{61 + 109 - 68 - 2}{153} = \frac{100}{153}\]

\[\boxed{\mathbf{10.}}\]

\[\textbf{а)}\ \left( \frac{31}{47} - \frac{6}{47} \right) - \left( \frac{11}{47} - \frac{6}{47} \right) =\]

\[= \frac{25}{47} - \frac{5}{47} = \frac{20}{47}\]

\[\textbf{б)}\ \left( \frac{29}{53} - \frac{9}{53} \right) - \left( \frac{21}{53} - \frac{9}{53} \right) =\]

\[= \frac{20}{53} - \frac{12}{53} = \frac{8}{53}\]

\[\textbf{в)}\ \frac{17}{27} - \left( \frac{2}{27} + \left( \frac{9}{27} - \frac{4}{27} \right) \right) =\]

\[= \frac{17}{27} - \left( \frac{2}{27} + \frac{5}{27} \right) = \frac{17}{27} - \frac{7}{27} =\]

\[= \frac{10}{27}\]

\[\textbf{г)}\ \frac{18}{29} - \left( \frac{3}{29} + \left( \frac{16}{29} - \frac{11}{29} \right) \right) =\]

\[= \frac{18}{29} - \left( \frac{3}{29} + \frac{5}{29} \right) = \frac{18}{29} - \frac{8}{29} =\]

\[= \frac{10}{29}\]

\[\boxed{\mathbf{11.}}\]

\[1)\ не\ может;\]

\[2)\ может;\]

\[3)\ верно;\]

\[4)\ неверно;\]

\[5)\ верно;\]

\[6)\ верно.\]