\[Стр.\ 12.\]
\[\boxed{\mathbf{2.}}\]
\[\textbf{а)}\frac{3}{5} < \frac{7}{8}\]
\[\textbf{б)}\ \frac{4}{7} < \frac{4}{5}\]
\[\textbf{в)}\ \frac{5}{8} < \frac{3}{4}\]
\[\textbf{г)}\ \frac{3}{6} = \frac{5}{10}\]
\[\textbf{д)}\ \frac{4}{12} = \frac{1}{3}\]
\[\textbf{е)}\ \frac{1}{2} = \frac{3}{6}\]