Решебник по математике 5 класс Ерина Виленкин рабочая тетрадь Часть 1, 2 Часть 1 | Страница 67

Авторы:
Год:2023
Тип:рабочая тетрадь
Часть:1, 2
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Страница 67

\[Страница\ 67.\]

\[\boxed{\mathbf{4}.}\]

\[a\] \[9\] \[4\] \[7\] \[8\] \[8\] \[5\] \[10\] \[100\] \[1\] \[0\]
\[a^{2}\] \[81\] \[16\] \[49\] \[64\] \[64\] \[25\] \[100\] \[10\ 000\] \[1\] \[0\]

\[\boxed{\mathbf{5}.}\]

\[a\] \[4\] \[2\] \[5\] \[1\] \[3\] \[10\] \[40\] \[30\] \[9\] \[6\] \[7\]
\[a^{3}\] \[64\] \[8\] \[125\] \[1\] \[27\] \[1000\] \[64\ 000\] \[27\ 000\] \[729\] \[216\] \[343\]

\[\boxed{\mathbf{6}.}\]

\[a\] \[1\] \[2\] \[3\] \[4\] \[5\] \[6\] \[7\] \[8\] \[9\] \[10\]
\[a^{2}\] \[1\] \[4\] \[9\] \[16\] \[25\] \[36\] \[49\] \[64\] \[81\] \[100\]
\[a^{3}\] \[1\] \[8\] \[27\] \[64\] \[125\] \[216\] \[343\] \[512\] \[729\] \[1000\]

\[\boxed{\mathbf{7}.}\]

\[\textbf{а)}\ x^{2} = 81\]

\[x = 9.\]

\[\textbf{б)}\ y^{3} = 27\]

\[y = 3.\]

\[\textbf{в)}\ a^{2} = 49\]

\[a = 7.\]

\[\textbf{г)}\ z^{3} = 729\]

\[z = 9.\]

\[\textbf{д)}\ a \cdot a = 36\]

\[a = 6.\]

\[\textbf{е)}\ x \cdot x \cdot x = 1\]

\[x = 1.\]

\[\textbf{ж)}\ a \cdot a = 100\]

\[a = 10.\]

\[\textbf{з)}\ y \cdot y \cdot y = 125\]

\[y = 5.\]

\[\textbf{и)}\ x \cdot x = 9\]

\[x = 3.\]

\[к)\ a \cdot a \cdot a = 0\]

\[a = 0.\]

\[\boxed{\mathbf{8}.}\]

\[\textbf{а)}\ (3 + 4)^{2} = 7^{2} = 49\]

\[\textbf{б)}\ 7^{2} + 5^{2} = 49 + 25 = 74\]

\[\textbf{в)}\ 8^{3} + 3 = 512 + 3 = 515\]

\[\textbf{г)}\ (8 + 2)^{3} = 10^{3} = 1000\]

\[\textbf{д)}\ (6 - 2)^{2}\ :(6 - 2) = 4^{2}\ :4 =\]

\[= 16\ :4 = 4\]

\[\textbf{е)}\ 9^{3} - 4^{3} = 729 - 64 = 665\]

\[\textbf{ж)}\ 4^{2} \cdot 11 = 8 \cdot 11 = 88\]

\[\textbf{з)}\ \left( 9^{3} - 5^{3} \right)\ :(8 - 6) =\]

\[= (729 - 125)\ :2 = 604\ :2 =\]

\[= 302\]

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