Решебник по математике 5 класс Виленкин ФГОС Часть 1, 2 Часть 2. Параграф 6. Десятичные дроби Задание 58

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\[\textbf{а)}\ \frac{8}{13} + \frac{3}{13} = \frac{11}{13};\ \]

\[\textbf{б)}\ \frac{31}{60} + \frac{29}{60} = \frac{60}{60} = 1;\ \]

\[\textbf{в)}\ 18 + \frac{4}{19} = 18\frac{4}{19};\ \]

\[\textbf{г)}\ 23 + \frac{9}{10} = 23\frac{9}{10};\ \]

\[\textbf{д)}\ 2\frac{7}{9} + \frac{8}{9} = 2\frac{15}{9} = 3\frac{6}{9} = 3\frac{2}{3};\ \]

\[\textbf{е)}\ 15\frac{8}{11} + 4\frac{3}{11} = 19\frac{11}{11} = 20;\ \]

\[\textbf{ж)}\ 4\frac{1}{2} + 3\frac{1}{4} = 4\frac{2}{4} + 3\frac{1}{4} = 7\frac{3}{4};\ \]

\[\textbf{з)}\ 5\frac{1}{7} + 3\frac{20}{21} = 5\frac{3}{21} + 3\frac{20}{21} =\]

\[= 8\frac{23}{21} = 9\frac{2}{21}\text{.\ \ \ }\]