Решебник по математике 5 класс Виленкин ФГОС Часть 1, 2 Часть 2. Параграф 6. Десятичные дроби Задание 46

\[\boxed{\text{\ 6.46.}}\]

\[\textbf{а)}\ n = \frac{7}{13}:\ \]

\[\frac{7}{13} - \frac{2}{13} = \frac{5}{13};\ \]

\[\frac{5}{13} + \frac{7}{13} = \frac{12}{13} > 1 \rightarrow нет;\ \]

\[\frac{12}{13} + \frac{3}{13} = \frac{15}{13};\ \]

\[\frac{15}{13} - \frac{5}{13} = \frac{10}{13}\text{.\ }\]

\[\textbf{б)}\ n = \frac{12}{13}:\ \]

\[\frac{12}{13} - \frac{2}{13} = \frac{10}{13};\ \]

\[\frac{10}{13} + \frac{7}{13} = \frac{17}{13} > 1 \rightarrow да;\ \]

\[\frac{17}{13} - \frac{5}{13} = \frac{12}{13};\ \]

\[\frac{12}{13} - \frac{6}{13} = \frac{6}{13}.\]

\[\textbf{в)}\ n = 1:\ \]

\[1 - \frac{2}{13} = \frac{13}{13} - \frac{2}{13} = \frac{11}{13};\ \]

\[\frac{11}{13} + \frac{7}{13} = \frac{18}{13} > 1 \rightarrow да;\ \]

\[\frac{18}{13} - \frac{5}{13} = \frac{13}{13};\ \]

\[\frac{13}{13} - \frac{6}{13} = \frac{7}{13}\text{.\ \ }\]