Решебник по математике 5 класс Виленкин ФГОС Часть 1, 2 Часть 2. Параграф 6. Десятичные дроби Задание 113

\[\boxed{\text{6.11}\text{3}\text{.}}\]

\[\textbf{а)}\ \frac{4}{7} + x = \frac{5}{7}\]

\[x = \frac{5}{7} - \frac{4}{7}\]

\[x = \frac{1}{7}\text{.\ }\]

\[Ответ:\ \frac{1}{7}\text{.\ }\]

\[\textbf{б)}\ m \cdot \frac{2}{9} = \frac{5}{9}\]

\[m = \frac{5}{9}\ :\frac{2}{9}\]

\[m = \frac{5}{9} \cdot \frac{9}{2}\]

\[m = \frac{5}{2} = 2\frac{1}{2}\text{.\ }\]

\[Ответ:\ 2\frac{1}{2}\text{.\ }\]

\[\textbf{в)}\ \frac{13}{15} - z = \frac{7}{45}\]

\[z = \frac{13}{15} - \frac{7}{45}\]

\[z = \frac{39}{45} - \frac{7}{45}\]

\[z = \frac{32}{45}\text{.\ }\]

\[Ответ:\ \frac{32}{45}\text{.\ }\]

\[\textbf{г)}\ n\ :\frac{3}{4} = \frac{8}{9}\]

\[n = \frac{8}{9} \cdot \frac{3}{4}\]

\[n = \frac{2}{3}\text{.\ }\]

\[Ответ:\ \frac{2}{3}\text{.\ \ \ }\]