\[\boxed{\text{5.493.}}\]
\[\textbf{а)}\ \ 10 \cdot \frac{2}{5} = 2 \cdot 2 = 4\]
\[\textbf{б)}\ 36 \cdot \frac{5}{9} = 4 \cdot 5 = 20\]
\[\textbf{в)}\ \frac{8}{27} \cdot \frac{1}{4} = \frac{2}{27}\]
\[\textbf{г)}\ \frac{3}{15} \cdot \frac{5}{6} = \frac{1 \cdot 1}{3 \cdot 2} = \frac{1}{6}\]