Решебник по математике 5 класс Виленкин ФГОС Часть 1, 2 Проверочные работы Проверочная работа №2. Повторение

\[\boxed{\mathbf{Проверочная\ работа\ №2.\ Повторение}}\]

\[\boxed{\text{1.}}\]

\[\textbf{а)}\ 1\frac{2}{3} + 3\frac{1}{3} - 2\frac{1}{3} = 4\frac{3}{3} - 2\frac{1}{3} =\]

\[= 2\frac{2}{3}\]

\[\textbf{б)}\ 2\frac{1}{6} + 3\frac{2}{3} + 4\frac{5}{6} = 6\frac{6}{6} + 3\frac{2}{3} =\]

\[= 7 + 3\frac{2}{3} = 10\frac{2}{3}\]

\[\textbf{в)}\ 7\frac{5}{12} - 1\frac{5}{6} + 3\frac{1}{24} =\]

\[= 7\frac{10}{24} + 3\frac{1}{24} - 1\frac{20}{24} =\]

\[= 10\frac{11}{24} - 1\frac{20}{24} = 9\frac{35}{24} - 1\frac{20}{24} =\]

\[= 8\frac{15}{24} = 8\frac{5}{8}\]

\[\textbf{г)}\ 9\frac{7}{18} - 6\frac{2}{36} + 11\frac{2}{9} =\]

\[= 9\frac{14}{36} + 11\frac{8}{36} - 6\frac{2}{36} =\]

\[= 20\frac{22}{36} - 6\frac{2}{36} = 14\frac{20}{36} = 14\frac{5}{9}\]

\[\boxed{\text{2.}}\]

\[\textbf{а)}\ 4,6 = 4\frac{6}{10} = 4\frac{3}{5}\]

\[\textbf{б)}\ 56,01 = 56\frac{1}{100}\]

\[\textbf{в)}\ 108,056 = 108\frac{56}{1000} =\]

\[= 108\frac{14}{250} = 108\frac{7}{125}\]

\[\textbf{г)}\ 0,000006 = \frac{6}{1000000} =\]

\[= \frac{3}{500000}\]

\[\textbf{д)}\ 19,45 = 19\frac{45}{100} = 19\frac{9}{20}\]

\[\textbf{е)}\ 601,43021 = 601\frac{43021}{100000}\]

\[\boxed{\text{3.}}\]

\[= 361,04\ :2 - 84,045 =\]

\[= 180,52 - 84,045 = 76,475\]

\[= 986,7385 - 981,7384 =\]

\[= 5,0001\]

\[\boxed{\text{4.}}\]

\[P = 2 \cdot (a + b)\]

\[\textbf{а)}\ a = 15,5;b = 21,5:\]

\[P = 2 \cdot (15,5 + 21,5) = 2 \cdot 37 =\]

\[= 74.\]

\[\textbf{б)}\ P = 40;b = 16,23:\]

\[2 \cdot (a + 16,23) = 40\]

\[a + 16,23 = 40\ :2\]

\[a + 16,23 = 20\]

\[a = 20 - 16,23\]

\[a = 3,77.\]

\[\textbf{в)}\ P = 48;a = 11\frac{1}{4} = 11\frac{25}{100} =\]

\[= 11,25:\]

\[2 \cdot (11,25 + b) = 48\]

\[11,25 + b = 48\ :2\]

\[11,25 + b = 24\]

\[b = 24 - 11,25\]

\[b = 12,75.\]

\[\boxed{\text{5.}}\]

\[V = 107,73\ м^{3};\ \ a = 6,3\ м;\ \ \]

\[b = 5,7\ м:\]

\[V = abc\]

\[6,3 \cdot 5,7 \cdot c = 107,73\]

\[c = 107,73\ :35,91 =\]

\[= 10\ 773\ :3591\]

\[c = 3\ м.\]

\[Ответ:3\ м.\]

\[\boxed{\text{6.}}\]

\[\textbf{а)}\ \frac{4}{29} + \frac{3}{29} = \frac{7}{29}\ (км) -\]

\[заасфальтировали\ во\ второй\ \]

\[день.\]

\[\textbf{б)}\ \frac{4}{29} + \frac{7}{29} = \frac{11}{29}\ (км) -\]

\[заасфальтровали\ за\ два\ дня.\]