Решебник по математике 5 класс Мерзляк ФГОС Задание 987

\[\boxed{\ \mathbf{987\ (987)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]

\[320 \cdot 0,01 = 3,2\ (кг) - собрал\ \]

\[винограда.\]

\[Ответ:3,2\ кг.\]

\[\boxed{\mathbf{987}\mathbf{.}\mathbf{\ }}\]

\[1)\ \frac{5}{6} = \frac{55}{66};\ \ \ \ \frac{7}{11} = \frac{42}{66} \Longrightarrow\]

\[\Longrightarrow \frac{5}{6} > \frac{7}{11}\]

\[2)\ \frac{7}{13} = \frac{112}{208};\ \ \ \ \frac{7}{16} = \frac{91}{208} \Longrightarrow\]

\[\Longrightarrow \frac{7}{13} > \frac{7}{16}\]

\[{3)\ \frac{3}{8} = \frac{9}{24};\ \ \ \frac{1}{6} = \frac{4}{24} \Longrightarrow }{\Longrightarrow \frac{3}{8} > \frac{1}{6}}\]

\[4)\ \frac{5}{8} = \frac{25}{40};\ \ \ \ \frac{7}{10} = \frac{28}{40} \Longrightarrow\]

\[\Longrightarrow \frac{5}{8} < \frac{7}{10}\]

\[5)\ \frac{3}{7} = \frac{9}{21};\ \ \ \ \frac{9}{21} \Longrightarrow \frac{3}{7} = \frac{9}{21}\]

\[6)\ \frac{3}{5} = \frac{24}{40};\ \ \ \ \frac{5}{8} = \frac{25}{40} \Longrightarrow \frac{3}{5} < \frac{5}{8}\]

\[7)\ \frac{7}{12} = \frac{21}{36};\ \ \ \ \ \frac{11}{18} = \frac{22}{36} \Longrightarrow\]

\[\Longrightarrow \frac{7}{12} < \frac{11}{18}\]

\[8)\ \frac{10}{21} = \frac{20}{42};\ \ \ \ \frac{9}{14} = \frac{27}{42} \Longrightarrow\]

\[\Longrightarrow \frac{10}{21} < \frac{9}{14}\]