Решебник по математике 5 класс Мерзляк ФГОС Задание 972

 

\[\boxed{\ \mathbf{972\ (972)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 12 \cdot x = 112,8\]

\[x = 112,8\ :12\]

\[x = 9,4\ \]

\[Ответ:9,4.\]

\[2)\ 178,5\ :x = 21\]

\[x = 178,5\ :21\]

\[x = 8,5\]

\[Ответ:8,5.\]

\[3)\ x\ :3,2 = 10,5\]

\[x = 10,5 \cdot 3,2\]

\[x = 33,60\]

\[Ответ:33,6.\]

\[4)\ y + 27y = 0,952\]

\[28y = 0,952\]

\[y = 0,952\ :28\]

\[y = 0,034\]

\[Ответ:0,034.\]

\[5)\ 33m - m = 102,4\]

\[32m = 102,4\]

\[m = 102,4\ :32\]

\[m = 3,2\]

\[Ответ:3,2.\]

\[6)\ 2,7x - 1,3x + 3,6x = 2\]

\[5x = 2\]

\[x = 2\ :5\]

\[x = 0,4\]

\(Ответ:0,4.\)

\[\boxed{\mathbf{972}\mathbf{.}\mathbf{\ }}\]

\[1)\ \frac{4 \cdot 5}{25 \cdot 6} = \frac{2 \cdot 1}{5 \cdot 3} = \frac{2}{15}\]

\[2)\ \frac{8 \cdot 13}{39 \cdot 2} = \frac{4 \cdot 1}{3 \cdot 1} = \frac{4}{3} = 1\frac{1}{3}\]

\[3)\ \frac{3 \cdot 38}{19 \cdot 27} = \frac{1 \cdot 2}{1 \cdot 9} = \frac{2}{9}\]

\[4)\ \frac{2 \cdot 3 \cdot 4 \cdot 5}{4 \cdot 5 \cdot 6 \cdot 7} = \frac{1 \cdot 1 \cdot 1 \cdot 1}{1 \cdot 1 \cdot 1 \cdot 7} = \frac{1}{7}\]

\[5)\ \frac{6 \cdot 7 \cdot 8 \cdot 9 \cdot 10}{7 \cdot 9 \cdot 11 \cdot 12} =\]

\[= \frac{1 \cdot 1 \cdot 4 \cdot 1 \cdot 10}{1 \cdot 1 \cdot 11 \cdot 1} = \frac{40}{11} = 3\frac{7}{11}\]

\[6)\ \frac{3 \cdot 16 - 8 \cdot 3}{27} =\]

\[= \frac{3 \cdot (16 - 8)}{27} = \frac{1 \cdot 8}{9} = \frac{8}{9}\]

\[7)\ \frac{9 \cdot 13 + 9 \cdot 2}{54 \cdot 13} =\]

\[= \frac{9 \cdot (13 + 2)}{54 \cdot 13} = \frac{1 \cdot 15}{6 \cdot 13} =\]

\[= \frac{1 \cdot 5}{2 \cdot 13} = \frac{5}{26}\]

\[8)\ \frac{27 \cdot 15 - 7 \cdot 27}{9 \cdot 15 - 9 \cdot 11} =\]

\[= \frac{27 \cdot (15 - 7)}{9 \cdot (15 - 11)} = \frac{3 \cdot 8}{1 \cdot 4} =\]

\[= 3 \cdot 2 = 6\]

\[9)\ \frac{24 \cdot 2 + 6 \cdot 24}{60 \cdot 7 - 5 \cdot 60} =\]

\[= \frac{24 \cdot (2 + 6)}{60 \cdot (7 - 5)} = \frac{2 \cdot 8}{5 \cdot 2} = \frac{8}{5} =\]

\[= 1\frac{3}{5}\ \]