Решебник по математике 5 класс Мерзляк ФГОС Задание 770

\[\boxed{\mathbf{770\ (770)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{13}{5} = \frac{10 + 3}{5} = \frac{10}{5} + \frac{3}{5} =\]

\[= 2 + \frac{3}{5} = 2\frac{3}{5}\]

\[2)\frac{18}{11} = \frac{11 + 7}{11} = \frac{11}{11} + \frac{7}{11} =\]

\[= 1 + \frac{7}{11} = 1\frac{7}{11}\]

\[3)\ \frac{37}{12} = \frac{36 + 1}{12} = \frac{36}{12} + \frac{1}{12} =\]

\[= 3 + \frac{1}{12} = 3\frac{1}{12}\]

\[4)\ \frac{68}{23} = \frac{46 + 22}{23} = \frac{46}{23} + \frac{22}{23} =\]

\[= 2 + \frac{2}{23} = 2\frac{22}{23}\]

\[5)\ \frac{79}{12} = \frac{72 + 7}{12} = \frac{72}{12} + \frac{7}{12} =\]

\[= 6 + \frac{7}{12} = 6\frac{7}{12}\]

\[6)\ \frac{83}{18} = \frac{72 + 11}{18} = \frac{72}{18} + \frac{11}{18} =\]

\[= 4 + \frac{11}{18} = 4\frac{11}{18}\]

\[\boxed{\mathbf{770}\mathbf{\ (597)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 30\ :15 = 2\ (ч) - время\ \]

\[велосипедиста\ на\ пути\ из\ A\ в\ \]

\[B.\]

\[2)\ 30 \cdot 2 = 60\ (км) - пролетела\ \]

\[птица,\ так\ как\ она\ тоже\ летала\ \]

\[2\ часа.\]

\[Ответ:60\ км.\]