Решебник по математике 5 класс Мерзляк ФГОС Задание 513

 

\[\boxed{\mathbf{513\ (513)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]

Пояснение.

Решение.

\[1)\ (44 \cdot 58)\ :11 = 44\ :11 \cdot 58 =\]

\[= 4 \cdot 58 = 232\]

\[2)\ (69 \cdot 60)\ :30 =\]

\[= 69 \cdot (60\ :30) = 69 \cdot 2 = 138\]

\[3)\ (26 \cdot 20)\ :13 =\]

\[= (26\ :13) \cdot 20 = 2 \cdot 20 = 40\]

\[4)\ (63 \cdot 88)\ :21 =\]

\[= (63\ :21) \cdot 88 = 3 \cdot 88 = 264\]

\[5)\ (350 \cdot 48)\ :70 =\]

\[= (350\ :70) \cdot 48 = 5 \cdot 48 = 240\]

\[6)\ (47 \cdot 200)\ :50 =\]

\[= 47 \cdot (200\ :50) = 47 \cdot 4 =\]

\[= 188\]

\[7)\ (2 \cdot 17 \cdot 14)\ :28 =\]

\[= (28 \cdot 17)\ :28 =\]

\[= (28\ :28) \cdot 17 = 1 \cdot 17 = 17\]

\[8)\ (21 \cdot 18)\ :14 =\]

\[= (21 \cdot 18)\ :7\ :2 =\]

\[= (21\ :7) \cdot (18\ :2) = 3 \cdot 9 = 27\]

\[9)\ (5 \cdot 11 \cdot 32)\ :16 =\]

\[= 5 \cdot 11 \cdot (32\ :16) = 55 \cdot 2 =\]

\[= 110\]

\[\boxed{\ \mathbf{513.}}\]

\[1)\ 1\ км = 1000\ м\]

\[1000\ :250 = 4\ раза.\]

\[2)\ 2\ т = 20\ ц\]

\[20\ :4 = 5\ раз.\]

\[3)\ 3\ мин = 180\ с\]

\[180\ :3 = 60\ раз.\]