Решебник по математике 5 класс Мерзляк ФГОС Задание 1052

 

\[\boxed{\mathbf{1052\ (1051)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 9,88\ :2,6 = 3,8 - 2,06 =\]

\[= 1,74 \cdot 3,5 = 6,09\]

\[9,88\ :3,8 = 98,8\ :38 = 2,6\]

\[3,8 - 1,74 = 2,06\]

\[6,09\ :1,74 = 609\ :174 = 3,5\]

\[Ответ:\ \ a = 2,6;\ \ b = 2,06;\ \ \]

\[c = 3,5.\]

\[2)\ 6,2 \cdot 2,8 = 17,36 + 2,74 =\]

\[= 20,1\ :13,4 = 1,5\]

\[17,36\ :6,2 = 173,6\ :62 = 2,8\]

\[20,1 - 17,36 = 2,74\]

\[20,1\ :1,5 = 201\ :15 = 13,4\]

\[Ответ:\ \ x = 2,8;\ \ y = 2,74;\ \ \]

\[z = 13,4.\]

\[\boxed{\mathbf{1052}\mathbf{.}\mathbf{\ }}\]

\[1)\ \frac{2}{13} \cdot 5 = \frac{2 \cdot 5}{13} = \frac{10}{13}\]

\[2)\ \frac{4}{17} \cdot 3 = \frac{4 \cdot 3}{17} = \frac{12}{17}\]

\[3)\ \frac{8}{9} \cdot 2 = \frac{8 \cdot 2}{9} = \frac{16}{9} = 1\frac{7}{9}\]

\[4)\frac{4}{49} \cdot 7 = \frac{4 \cdot 7}{49} = \frac{4}{7}\]

\[5)\ 7 \cdot \frac{3}{40} = \frac{7 \cdot 3}{40} = \frac{21}{40}\]

\[6)\ 6 \cdot \frac{15}{18} = \frac{6 \cdot 15}{18} = \frac{1 \cdot 15}{3} = 5\]

\[7)\frac{7}{12} \cdot 24 = \frac{7 \cdot 24}{12} = 7 \cdot 2 = 14\]

\[8)\ 45 \cdot \frac{8}{15} = \frac{45 \cdot 8}{15} = 3 \cdot 8 = 24\]