\[\boxed{\mathbf{1031\ (1031)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]
\[\textbf{а)}\ S = ab - cd\]
\[\textbf{б)}\ S = b \cdot (a + d) - ac\ \]
\[\boxed{\mathbf{1031}\mathbf{.}\mathbf{\ }}\]
\[1 - \left( \frac{1^{\backslash 6}}{2} + \frac{1^{\backslash 3}}{4} + \frac{1}{12} \right) =\]
\[= 1 - \left( \frac{6}{12} + \frac{3}{12} + \frac{1}{12} \right) =\]
\[= 1 - \frac{10}{12} = 1^{\backslash 6} - \frac{5}{6} =\]
\[= \frac{1}{6}\ (часть) - денег\ Филиппок\ \]
\[потратил\ на\ конфеты.\]
\[Ответ:\ \frac{1}{6}\ \ часть\ денег.\]