\[\boxed{\mathbf{1025\ (1025)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]
\[\boxed{\mathbf{1025}\mathbf{.}\mathbf{\ }}\]
\[1)\ \frac{2^{\backslash 2}}{9} + \frac{5^{\backslash 3}}{6} = \frac{4 + 15}{18} = \frac{19}{18} =\]
\[= 1\frac{1}{18}\ (С)\ \]
\[2)\ 1^{\backslash 17} - \frac{5}{17} = \frac{17 - 5}{17} = \frac{12}{17}\ \ \ (Т)\]
\[3)\ 6 - 1\frac{4}{9} = 5\frac{9}{9} - 1\frac{4}{9} = 4\frac{5}{9}\ \ \ (Е)\]
\[4)\ 2\frac{1^{\backslash 2}}{3} - 1\frac{1^{\backslash 3}}{2} = 2\frac{2}{6} - 1\frac{3}{6} =\]
\[= 1\frac{8}{6} - 1\frac{3}{6} = \frac{5}{6}\ \ (К)\]
\[5)\ 1\frac{1^{\backslash 4}}{7} + 2\frac{3}{28} = 1\frac{4}{28} + 2\frac{3}{28} =\]
\[= 3\frac{7}{28} = 3\frac{1}{4}\ \ (Л)\]
\[6)\ \ 5\frac{1^{\backslash 2}}{6} - 4\frac{1^{\backslash 3}}{4} = 5\frac{2}{12} - 4\frac{3}{12} =\]
\[= 4\frac{14}{12} - 4\frac{3}{12} = \frac{11}{12}\ \ (О)\]
\[7)\ \frac{1^{\backslash 3}}{4} + \frac{1}{12} + \frac{2^{\backslash 4}}{3} = \frac{3 + 1 + 8}{12} =\]
\[= \frac{12}{12} = 1\ \ (В)\]