\[\boxed{\mathbf{1009\ (1009)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]
\[1)\ 302 - 298,8 = 3,2\ \left( \frac{м}{мин} \right) -\]
\[скорость\ сближения.\]
\[2)\ 30,4\ :3,2 = 9,5\ (мин) - за\ \]
\[это\ время\ мыши\ догонят\ \]
\[кота\ Леопольда.\]
\[Ответ:через\ 9,5\ минут.\]
\[\boxed{\mathbf{1009}\mathbf{.}\mathbf{\ }}\]
\[1)\ \frac{3^{\backslash 9}}{7} + \frac{4^{\backslash 7}}{9} = \frac{27 + 28}{63} = \frac{55}{63}\]
\[2)\ \frac{8^{\backslash 8}}{9} - \frac{7^{\backslash 9}}{8} = \frac{64 - 63}{72} = \frac{1}{72}\]
\[3)\ \frac{13}{15} - \frac{2^{\backslash 5}}{3} = \frac{13 - 10}{15} = \frac{3}{15} =\]
\[= \frac{1}{5}\]
\[4)\ \frac{20}{21} + \frac{3^{\backslash 3}}{7} = \frac{20 + 9}{21} = \frac{29}{21} =\]
\[= 1\frac{8}{21}\]
\[5)\ \frac{17^{\backslash 2}}{18} - \frac{11^{\backslash 3}}{12} = \frac{34 - 33}{36} =\]
\[= \frac{1}{36}\]
\[6)\ \frac{7^{\backslash 3}}{16} + \frac{1^{\backslash 8}}{6} = \frac{21 + 8}{48} = \frac{29}{48}\]
\[7)\ \frac{2^{\backslash 2}}{9} + \frac{5^{\backslash 3}}{6} = \frac{4 + 15}{18} = \frac{19}{18} =\]
\[= 1\frac{1}{18}\]
\[8)\ \frac{10^{\backslash 2}}{21} + \frac{9^{\backslash 3}}{14} = \frac{20 + 27}{42} = \frac{47}{42} =\]
\[= 1\frac{5}{42}\]
\[9)\ \frac{7^{\backslash 5}}{9} - \frac{4^{\backslash 3}}{15} = \frac{35 - 12}{45} = \frac{23}{45}\]
\[10)\ \frac{9^{\backslash 2}}{14} - \frac{3^{\backslash 4}}{7} + \frac{15}{28} =\]
\[= \frac{18 - 12 + 15}{28} = \frac{21}{28} = \frac{3}{4}\]
\[11)\ \frac{1^{\backslash 4}}{6} + \frac{1^{\backslash 6}}{4} - \frac{1^{\backslash 3}}{8} =\]
\[= \frac{4 + 6 - 3}{24} = \frac{7}{24}\]
\[12)\ \frac{13^{\backslash 5}}{18} - \frac{29^{\backslash 2}}{45} + \frac{8^{\backslash 6}}{15} =\]
\[= \frac{65 - 58 + 48}{90} = \frac{55}{90} = \frac{11}{18}\]