Решебник по математике 4 класс Моро Часть 1, 2 Часть 1 Задание 91

\[\boxed{\text{91\ (91).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Пояснение.

Решение.

\[1)\ 40\ :8 + 2 \cdot 100 = 5 + 200 =\]

\[= 205.\]

\[2)\ 40\ :(8 + 2) \cdot 100 =\]

\[= 40\ :10 \cdot 100 = 4 \cdot 100 = 400.\]

\[3)\ (40\ :8 + 2) \cdot 100 =\]

\[= (5 + 2) \cdot 100 = 7 \cdot 100 = 700.\]

\[4)\ 100 - (40 + 36)\ :4 =\]

\[= 100 - (10 + 9) =\]

\[= 100 - 10 - 9 = 90 - 9 = 81.\]

\[5)\ (100 - 40 + 36)\ :4 =\]

\[= (60 + 36)\ :4 = 96\ :4 =\]

\[= (80 + 16)\ :4 =\]

\[= 20 + 4 = 24.\]

\[6)\ 100 - (40 + 36\ :4) =\]

\[= 100 - (40 + 9) =\]

\[= 100 - 40 - 9 = 60 - 9 = 51.\]

\[7)\ 900\ :9 - 6 \cdot 10 =\]

\[= 100 - 60 = 40.\]

\[8)\ 600\ :100 + 50 \cdot 10 =\]

\[= 6 + 500 = 506.\]

\[9)\ 70 \cdot 5 + 3 \cdot 100 =\]

\[= 350 + 300 = 650.\ \]