Решебник по математике 3 класс Моро ФГОС Часть 1, 2 Часть 2 | Страница 37

\[Страница\ 37.\ Тест\]

\[\boxed{\mathbf{Вариант}\mathbf{\ 2}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[\boxed{\mathbf{1}\mathbf{.}\mathbf{\ }}\]

\[(12 + 9) \cdot 4 = 12 \cdot 4 + 9 \cdot 4\]

\[\boxed{\mathbf{2}\mathbf{.}\mathbf{\ }}\]

\[14 \cdot 7 = (10 + 4) \cdot 7 = 10 \cdot 7 +\]

\[+ 4 \cdot 7 = 70 + 28 = 98\]

\[Ответ:98.\]

\[\boxed{\mathbf{3}\mathbf{.}\mathbf{\ }}\]

\[74\ :2 = (60 + 14)\ :2 =\]

\[= 60\ :2 + 14\ :2 = 30 + 7 = 37\]

\[Ответ:37.\]

\[\boxed{\mathbf{4}\mathbf{.}\mathbf{\ }}\]

\[(24 + 60)\ :12 = 24\ :12 +\]

\[+ 60\ :12\]

\[\boxed{\mathbf{5}\mathbf{.}\mathbf{\ }}\]

\[(34 + 62)\ :16 = 96\ :16 = 6\]

\[Ответ:6.\]

\[\boxed{\mathbf{6}\mathbf{.}\mathbf{\ }}\]

\[17 \cdot 4 = (10 + 7) \cdot 4 = 10 \cdot 4 +\]

\[+ 7 \cdot 4 = 40 + 28 = 68\]

\[Ответ:68.\]

\[\boxed{\mathbf{7}\mathbf{.}\mathbf{\ }}\]

\[При\ делении\ на\ 4\ остаток\ \]

\[может\ быть\ таким:\]

\[1,\ \ \ 2,\ \ \ 3.\]

\[\boxed{\mathbf{8}\mathbf{.}\mathbf{\ }}\]

\[37\ :7 = 5\ (ост.\ 2)\]

\[Ответ:5\ (ост.\ 2).\]

\[\boxed{\mathbf{9}\mathbf{.}\mathbf{\ }}\]

\[75\ :15 = 5\]

\[Ответ:5.\]

\[\boxed{\mathbf{10}\mathbf{.}\mathbf{\ }}\]

\[7\ :9 = 0\ (ост.\ 7)\]

\[Ответ:0\ (ост.\ 7).\]

\[\boxed{\mathbf{11}\mathbf{.}\mathbf{\ }}\]

\[64\ :\ \boxdot = 80\ :5\]

\[64\ :\ \boxdot = 16\]

\[\boxdot = 64\ :16\]

\[\boxdot = 4.\]

\[Ответ:4.\]