Решебник по геометрии 9 класс Мерзляк Задание 2

\[1)\sin a = \frac{1}{3}:\]

\[\sin(180{^\circ} - a) = \sin a = \frac{1}{3}.\]

\[2)\cos a = 0,7:\]

\[\cos(180{^\circ} - a) = - \cos a = - 0,7.\]

\[3)\cos a = - \frac{4}{9}:\]

\[\cos(180{^\circ} - a) = - \cos a = \frac{4}{9}.\]

\[4)\ tg\ a = - 5:\]

\[\text{tg}(180{^\circ} - a) = - tg\ a = 5.\]

\[5)\ ctg\ a = - \frac{1}{3}:\]

\[\text{ctg}(180{^\circ} - a) = - ctg\ a = \frac{1}{3}.\]