\[Схематический\ рисунок.\]
\[Дано:\]
\[\mathrm{\Delta}ABC\sim\mathrm{\Delta}A_{1}B_{1}C_{1};\]
\[\angle A = \angle A_{1};\ \]
\[\angle B = \angle B_{1};\]
\[AB = 6\ см;\ \]
\[BC = 7\ см;\]
\[AC = 10\ см;\ \]
\[A_{1}B_{1} = 9\ см.\]
\[Найти:\]
\[B_{1}C_{1};\ A_{1}C_{1}.\]
\[Решение.\]
\[\frac{\text{BC}}{B_{1}C_{1}} = \frac{\text{AC}}{A_{1}C_{1}} = \frac{\text{AB}}{A_{1}B_{1}} = \frac{2}{3};\]
\[B_{1}C_{1} = \frac{3}{2}BC = \frac{3}{2} \bullet 7 = 10,5\ см.\]
\[A_{1}C_{1} = \frac{3}{2}AC = \frac{3}{2} \bullet 10 = 15\ см.\]
\[Ответ:\ \ B_{1}C_{1} = 10,5\ см;\ \]
\[\text{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }A_{1}C_{1} = 15\ см.\]