\[\boxed{\mathbf{964.ОК\ ГДЗ - домашка\ на}\ 5}\]
\[(x - 3)^{2} + (y - 5)^{2} = 25\]
\[\textbf{а)}\ x = 3:\]
\[(3 - 3)^{2} + {(y - 5)}^{2} = 25;\]
\[{(y - 5)}^{2} = 25;\]
\[y_{1} = 10;\]
\[y_{2} = 0.\]
\[A(3;10)\ и\ B(3;0).\]
\[\textbf{б)}\ y = 5:\]
\[{(x - 3)}^{2} + {(5 - 5)}^{2} = 25;\]
\[(x - 3)^{2} = 25;\]
\[x_{1} = - 2;\]
\[x_{2} = 8.\]
\[C( - 2;5)\ и\ D(8;5).\]
\[\boxed{\mathbf{964.еуроки - ответы\ на\ пятёрку}}\]
\[1)\ Построим\ векторы\ \overrightarrow{x}\ и\ \overrightarrow{y}\text{.\ \ }\]
\[\textbf{а)}\ \overrightarrow{x} + 2\overrightarrow{y};\]
\[\textbf{б)}\frac{1}{2}\overrightarrow{y} + \overrightarrow{x};\]
\[\textbf{в)}\ 3\overrightarrow{x} + \frac{1}{2}\overrightarrow{y};\]
\[\textbf{г)}\ 1\frac{1}{2}\overrightarrow{x} - 3\overrightarrow{y};\]
\[\textbf{д)}\ 0\overrightarrow{x} + 4\overrightarrow{y};\]
\[\textbf{е)} - 2\overrightarrow{x} + 0\overrightarrow{y}.\]
\[2)\ Построим\ векторы\ \overrightarrow{x}\ и\ \overrightarrow{y}\text{.\ \ }\]
\[\textbf{а)}\ \overrightarrow{x} + 2\overrightarrow{y};\]
\[\textbf{б)}\frac{1}{2}\overrightarrow{y} + \overrightarrow{x};\]
\[\textbf{в)}\ 3\overrightarrow{x} + \frac{1}{2}\overrightarrow{y};\]
\[\textbf{г)}\ 1\frac{1}{2}\overrightarrow{x} - 3\overrightarrow{y};\]
\[\textbf{д)}\ 0\overrightarrow{x} + 4\overrightarrow{y};\]
\[\textbf{е)} - 2\overrightarrow{x} + 0\overrightarrow{y}.\]