\[\boxed{\mathbf{548.ОК\ ГДЗ - домашка\ на}\ 5}\]
\[Рисунок\ по\ условию\ задачи:\]
\[\mathbf{Дано:}\]
\[\mathrm{\Delta}\text{ABC}\sim\mathrm{\Delta}A_{1}B_{1}C_{1};\]
\[\frac{\text{BC}}{B_{1}C_{1}} = k;\]
\[\text{BC} = 1,4\ м;\]
\[B_{1}C_{1} = 56\ см.\]
\[\mathbf{Найти:}\]
\[\frac{P_{\text{ABC}}}{P_{A_{1}B_{1}C_{1}}} - ?\]
\[\mathbf{Решение.}\]
\[1)\frac{\text{BC}}{B_{1}C_{1}} = \frac{140}{56} = 2,5;\]
\[k = 2,5.\]
\[2)\ \mathrm{\Delta}\text{ABC}\sim\mathrm{\Delta}A_{1}B_{1}C_{1}\ (по\ условию):\]
\[\frac{P_{\text{ABC}}}{P_{A_{1}B_{1}C_{1}}} = k\]
\[\frac{P_{\text{ABC}}}{P_{A_{1}B_{1}C_{1}}} = 2,5.\]
\[\mathbf{Ответ:}2,5\mathbf{.}\]
\[\boxed{\mathbf{548.еуроки - ответы\ на\ пятёрку}}\]
\[\textbf{а)}\ a = 8,5\ см;b = 3,2\ см:\]
\[S = 8,5 \bullet 3,2 = 27,2\ см^{2}.\]
\[\textbf{б)}\ a = 2\sqrt{2}\ см;b = 3\ см:\]
\[S = 2\sqrt{2} \bullet 3 = 6\sqrt{2}\ см^{2}.\]
\[\textbf{в)}\ S = 684,8\ см^{2};a = 32\ см:\]
\[b = 684,8\ :32 = 21,4\ см.\]
\[\textbf{г)}\ S = 12,5\ см^{2};b = 4,5\ см:\]
\[a = 12,5\ :4,5 = 2,7\ см.\]