\[\boxed{\mathbf{46.}\mathbf{ОК\ ГДЗ - домашка\ на}\ 5}\]
\[\textbf{а)}\ \angle AOX = 40{^\circ};\]
\[\angle BOX = 60{^\circ};\]
\[\angle AOB = 20{^\circ};\]
\[\angle COB = 20{^\circ};\]
\[\angle DOX = 130{^\circ};\]
\[\textbf{б)}\ \angle COB = \ \angle AOB = 20{^\circ};\]
\[\textbf{в)}\ \angle AOX = \angle COA = 40{^\circ};\ \]
\[\angle AOB = \angle COB = 20{^\circ};\ \]
\[\angle DOC = \angle ZOD = 50{^\circ};\]
\[\textbf{г)}\ \angle BOA = 20{^\circ};\ \]
\[\angle COA = 40{^\circ};\ \]
\[\angle DOA = 90{^\circ};\ \]
\[\angle ZOA = 140{^\circ}.\]
\[\boxed{\mathbf{46.еуроки - ответы\ на\ пятёрку}}\]
\[Начертим\ луч\ \text{OA.}\]
\[\mathbf{С\ помощью\ транспортира\ \ }\]
\[\mathbf{отложим\ от\ него\ нужные\ углы.\ }\]