\[Схематический\ рисунок.\]
\[Дано:\ \ \]
\[BA - биссектриса\ \angle DBK;\]
\[\angle ABC = 72{^\circ};\]
\[\angle ABD = 5\angle CBD.\]
\[Найти:\]
\[\angle DBK.\]
\[Решение:\]
\[1)\ \angle ABC = \angle ABD + \angle CBD\]
\[\angle ABC = 5\angle CBD + \angle CBD\]
\[6\angle CBD = 72{^\circ}\ \ \ \]
\[\angle CBD = 12{^\circ}.\]
\[2)\ \angle DBK = \angle ABD + \angle ABK\]
\[\angle DBK = \angle ABD + \angle ABD\]
\[\angle DBK = 2\angle ABD = 10\angle CBD\]
\[\angle DBK = 10 \bullet 12{^\circ} = 120{^\circ}.\]
\[Ответ:\ \ 120{^\circ};\ тупой.\]