Решебник по геометрии 11 класс. Атанасян ФГОС 564

\[\boxed{\mathbf{564.}ОК\ ГДЗ\ –\ домашка\ на\ 5}\]

\[Рисунок\ к\ задаче:157.\]

\[\textbf{а)}\ \overrightarrow{A_{1}D_{1}} = \overrightarrow{\text{BC}}:\]

\[\overrightarrow{\text{AB}} + \overrightarrow{A_{1}D_{1}} = \overrightarrow{\text{AB}} + \overrightarrow{\text{BC}} = \overrightarrow{\text{AC}}.\]

\[\textbf{б)}\ По\ правилу\ \]

\[параллелограмма:\]

\[\overrightarrow{\text{AB}} + \overrightarrow{AD_{1}} = \overrightarrow{AC_{1}}.\]

\[\textbf{в)}\ \overrightarrow{\text{DA}} = \overrightarrow{\text{CB}};\ \ \ \overrightarrow{B_{1}B} = \overrightarrow{C_{1}C}:\]

\[\overrightarrow{\text{DA}} + \overrightarrow{B_{1}B} = \overrightarrow{\text{CB}} + \overrightarrow{C_{1}\text{C\ }} =\]

\[= \overrightarrow{C_{1}C} + \overrightarrow{\text{CB}} = \overrightarrow{C_{1}B}.\]

\[\textbf{г)}\ \overrightarrow{\text{DB}} = \overrightarrow{D_{1}B_{1}}:\ \]

\[\overrightarrow{DD_{1}} + \overrightarrow{\text{DB}} = \overrightarrow{DD_{1}} + \overrightarrow{D_{1}B_{1}} = \overrightarrow{DB_{1}}.\]

\[\textbf{д)}\ \overrightarrow{\text{BC}} = \overrightarrow{B_{1}C_{1}}:\]

\[\overrightarrow{DB_{1}} + \overrightarrow{\text{BC}} = \overrightarrow{DB_{1}} + \overrightarrow{B_{1}C_{1}} = \overrightarrow{DC_{1}}.\]