Решебник по геометрии 10 класс Атанасян ФГОС 646

\[\boxed{\mathbf{646.}ОК\ ГДЗ\ –\ домашка\ на\ 5}\]

\[\overrightarrow{a}\left\{ 5; - 1;1 \right\};\ \ \overrightarrow{b}\left\{ - 2;1;0 \right\};\ \ \]

\[\overrightarrow{c}\left\{ 0;0,2;0 \right\};\ \ \overrightarrow{d}\left\{ - \frac{1}{3};2\frac{2}{5};\ - \frac{1}{7} \right\}.\]

\[\textbf{а)}\ \overrightarrow{a} - \overrightarrow{b}\left\{ 7; - 2;1 \right\}.\]

\[\textbf{б)}\ \overrightarrow{b} - \overrightarrow{a}\left\{ - 7;2; - 1 \right\}.\]

\[\textbf{в)}\ \overrightarrow{a} - \overrightarrow{c}\left\{ 5; - 1,2;1 \right\}.\]

\[\textbf{г)}\ \overrightarrow{d} - \overrightarrow{a}\left\{ - 5\frac{1}{3};3\frac{2}{5}; - 1\frac{1}{7} \right\}.\]

\[\textbf{д)}\ \overrightarrow{c} - \overrightarrow{d}\left( \frac{1}{3}; - 2,2;\ \frac{1}{7} \right\}.\]

\[\textbf{е)}\ \overrightarrow{a} - \overrightarrow{b} + \overrightarrow{c}\left\{ 7; - 1,8;1 \right\}.\]

\[\textbf{ж)}\ \overrightarrow{a} - \overrightarrow{b} - \overrightarrow{c}\left\{ 7; - 2,2;1 \right\}.\]

\[\textbf{з)}\ 2\overrightarrow{a}\left\{ 10; - 2;2 \right\}.\]

\[\textbf{и)} - 3\overrightarrow{b}\left\{ 6; - 3;0 \right\}.\]

\[к) - 6\overrightarrow{c}\left\{ 0; - 1,2;0 \right\}.\]

\[л) - \frac{1}{3}\overrightarrow{d}\left\{ \frac{1}{9}; - \frac{4}{5};\frac{1}{21} \right\}.\]

\[м)\ 0,2\overrightarrow{b}\left\{ - 0,4;0,2;0 \right\}.\]