\[\boxed{\text{965\ (965).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[y = x^{2} + bx + c;\ \ \ \ (0; - 3);\ \ \ \ \]
\[\left( \frac{1}{2};0 \right)\]
\[y = x^{2} + 5,5x - 3\]
\[По\ теореме\ Виета:\]
\[x_{1} \cdot x_{2} = c = - 3,\]
\[x_{2} = - \frac{3}{x_{1}} = - \frac{3}{0,5} = - 6.\]
\[Ответ:b = 5,5;\ \ c = - 3;\ \ \]
\[точка\ пересечения\ \]
\[с\ осью\ x \Longrightarrow \left( \frac{1}{2};0 \right)и\ ( - 6;0)\text{.\ }\]