Решебник по алгебре 9 класс Макарычев Задание 836

\[\boxed{\text{836\ (836).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[50 = 1 \cdot 2 \cdot 3 \cdot 4 \cdot 5 \cdot \ldots \cdot 50.\]

\[\textbf{а)}\ 100 = 50 \cdot 2 \Longrightarrow 50!\ делится\ \]

\[на\ 100.\]

\[\textbf{б)}\ 305 = 5 \cdot 61 \Longrightarrow 50!\ не\ \]

\[делится\ на\ 305.\]

\[\textbf{в)}\ 1550 = 5 \cdot 10 \cdot 31 \Longrightarrow 50!\ \]

\[делится\ на\ 1550.\]

\[\boxed{\text{836.}\text{\ }\text{ОК\ ГДЗ\ -\ домашка\ на\ 5}}\]

\[2x^{5} + x^{4} - 10x^{3} - 5x^{2} + 8x + 4 = 0\]

\[(2x + 1)\left( x^{4} - 5x^{2} + 4 \right) = 0\]

\[1)\ 2x + 1 = 0,\ \ x = - \frac{1}{2},\]

\[2)\ x^{4} - 5x^{2} + 4 = 0\]

\[x^{2} = c,\ \ c \geq 0,\]

\[c² - 5c + 4 = 0\]

\[D = 25 - 16 = 9,\]

\[c_{1} = \frac{5 + 3}{2} = 4,\ \ \]

\[c_{2} = \frac{5 - 3}{2} = 1,\]

\[x^{2} = 4,\ \ x = \pm 2,\]

\[x^{2} = 1,\ \ x = \pm 1.\]

\[Ответ:x = - \frac{1}{2},x = \ \pm 2,\ x = \pm 1.\]