Решебник по алгебре 9 класс Макарычев Задание 588

\[\boxed{\text{588\ (}\text{с}\text{).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[x_{1} = 2,5;\ \ x_{6} = 4\]

\[x_{n} = x_{1} + d(n - 1)\]

\[x_{n} - x_{1} = x_{1} + d(n - 1) - x_{1} =\]

\[= d(n - 1)\]

\[d = \frac{x_{n} - x_{1}}{n - 1} = \frac{x_{6} - x_{1}}{5} = 0,3.\]

\[x_{1} = 2,5\ \]

\[x_{2} = 2,8\ \]

\[x_{3} = 3,1\]

\[x_{4} = 3,4\]

\[x_{5} = 3,7\]

\[x_{6} = 4.\]

\[\boxed{\text{588.}\text{\ }\text{ОК\ ГДЗ\ -\ домашка\ на\ 5}}\]

\[\left\{ \begin{matrix} y \geq x^{2}\text{\ \ \ \ \ \ \ } \\ 2y + x \leq 5 \\ \end{matrix} \right.\ \]