\[\boxed{\text{1036\ (1036).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[(2x + 1)\left( x^{4} - 5x^{2} + 4 \right) = 0\]
\[1)\ 2x + 1 = 0,\ \ x = - \frac{1}{2},\]
\[2)\ x^{4} - 5x^{2} + 4 = 0\]
\[x^{2} = c,\ \ c \geq 0,\]
\[c² - 5c + 4 = 0\]
\[D = 25 - 16 = 9,\]
\[c_{1} = \frac{5 + 3}{2} = 4,\ \ \]
\[c_{2} = \frac{5 - 3}{2} = 1,\]
\[x^{2} = 4,\ \ x = \pm 2,\]
\[x^{2} = 1,\ \ x = \pm 1.\]
\[Ответ:x = - \frac{1}{2},x = \ \pm 2,\ x = \pm 1.\]