Решебник по алгебре 9 класс Макарычев Задание 1022

\[\boxed{\text{1022\ (1022).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[y = \frac{6 - 2x}{3}\]

\[\textbf{а)}\ f(x) = 0:\]

\[\frac{6 - 2x}{3} = 0\]

\[6 - 2x = 0\]

\[при\ \ x = 3.\]

\[\textbf{б)}\ f(x) < 0:\ \ \]

\[\frac{6 - 2x}{3} < 0\]

\[6 - 2x < 0\]

\[при\ x > 3.\]

\[\textbf{в)}\ f(x) \geq 0:\ \]

\[\frac{6 - 2x}{3} \geq 0\]

\[6 - 2x \geq 0\]

\[при\ \ x \leq 3.\]

\[y = \frac{6 - 2x}{3}.\]