\[\boxed{\mathbf{946\ (946).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]
\[\frac{3x + 5}{4} - 1 \leq \frac{x - 2}{3} + x\text{\ \ \ \ }| \cdot 12\]
\[9x + 15 - 12 \leq 4x - 8 + 12x\]
\[- 7x \leq - 11\]
\[x \geq \frac{11}{7}\text{\ \ }\]
\[x \geq 1\frac{4}{7}\]
\[x_{\min} = 2\]
\[Ответ:x = 2.\]