Решебник по алгебре 9 класс Мерзляк Задание 854

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\[b_{1} = 6;\ \ b_{5} = 486\]

\[b_{5} = b_{1}q^{4}\text{\ \ }\]

\[q^{4} = \frac{b_{5}}{b_{1}} = \frac{486}{6} = 81 \Longrightarrow \ \ q = \pm 3\]

\[при\ q = 3:\ \ \]

\[b_{2} = 6 \cdot 3 = 18,\ \ \]

\[b_{3} = 18 \cdot 3 = 54,\ \ \]

\[b_{4} = 54 \cdot 3 = 162;\]

\[при\ q = - 3:\ \ \]

\[b_{2} = 6 \cdot ( - 3) = - 18,\ \ \]

\[b_{3} = - 18 \cdot ( - 3) = 54,\ \]

\[b_{4} = 54 \cdot ( - 3) = - 162.\]

\[Ответ:6,\ 18,\ 54,\ 162,\ 486\ \ или\ \]

\[\ 6,\ - 18,\ 54,\ - 162,\ 486.\]