\[\boxed{\text{330\ (330).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[\frac{3}{x} = \sqrt{x} + 2;\ x \neq 0;\ \ x \geq 0\]
\[y = \frac{3}{x}\]
\[x\] | \[1\] | \[3\] | \[9\] | \[0,5\] | \[- 1\] | \[- 3\] | \[- 9\] | \[- 0,5\] |
---|---|---|---|---|---|---|---|---|
\[y\] | \[3\] | \[1\] | \[0,5\] | \[6\] | \[- 3\] | \[- 1\] | \[- 0,5\] | \[- 6\] |
\[y = \sqrt{x} + 2\]
\[1)\ y = \sqrt{x}\]
\[x\] | \[1\] | \[4\] | \[9\] |
---|---|---|---|
\[y\] | \[1\] | \[2\] | \[3\] |
\[2)\ y = \sqrt{x} + 2\]
\[Ответ:x = 1.\]