\[\boxed{\mathbf{114.}}\]
\[\textbf{а)}\]
\[\textbf{б)}\ P\left( \text{SAC} \right) = \frac{1}{2} \cdot \frac{2}{3} = \frac{1}{3};\]
\[P\left( \text{SAGF} \right) = \frac{1}{2} \cdot \frac{1}{3} \cdot \frac{1}{4} = \frac{1}{24}\text{.\ }\]