\[\boxed{\mathbf{503\ (503).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]
\[1)\ \frac{\sqrt{48}}{\sqrt{3}} = \sqrt{16} = 4\]
\[2)\ \frac{\sqrt{150}}{\sqrt{6}} = \sqrt{25} = 5\]
\[3)\ \frac{\sqrt{6,3}}{\sqrt{0,7}} = \sqrt{9} = 3\]
\[4)\ \frac{\sqrt{98}}{\sqrt{242}} = \sqrt{\frac{98}{242}} = \sqrt{\frac{49}{121}} = \frac{7}{11}\]
\[5)\ \frac{\sqrt{6} \cdot \sqrt{2}}{\sqrt{3}} = \frac{\sqrt{12}}{\sqrt{3}} = \sqrt{4} = 2\]