Решебник по алгебре 8 класс Мерзляк ФГОС Задание 379

 

\[\boxed{\text{379\ (379).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Пояснение.

Решение.

\[1)\ \sqrt{9} = 3\]

\[2)\ \sqrt{49} = 7\]

\[3)\ \sqrt{100} = 10\]

\[4)\sqrt{225} = 15\]

\[5)\ \sqrt{0,25} = 0,5\]

\[6)\ \sqrt{0,01} = 0,1\]

\[7)\ \sqrt{1,21} = 1,1\]

\[8)\ \sqrt{1,96} = 1,4\]

\[9)\ \sqrt{400} = 20\]

\[10)\ \sqrt{3600} = 60\]

\[11)\ \sqrt{\frac{1}{64}} = \frac{1}{8}\]

\[12)\ \ \sqrt{\frac{4}{9}} = \frac{2}{3}\]

\[13)\ \sqrt{1\frac{9}{16}} = \sqrt{\frac{25}{16}} = \frac{5}{4}\]

\[14)\ \sqrt{3\frac{6}{25}} = \sqrt{\frac{81}{25}} = \frac{9}{5}\]

\[15)\ \sqrt{0,0004} = 0,02\]

\[16)\ \sqrt{0,000025} = 0,005\]

\[\boxed{\text{379.}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[y = x^{3};\ \ y = x;\]

\[x^{3} = x\]

\[x^{3} - x = 0\]

\[x\left( x^{2} - 1 \right) = 0\]

\[x(x - 1)(x + 1) = 0\]

\[x = 0;\ \ x = - 1;\ \ x = 1;\]

\[y = 0;\ \ y = - 1;\ \ \ y = 1.\]

\[Ответ:(0;0);( - 1; - 1);(1;1).\]