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МатематикаРешебник по алгебре 8 класс Мерзляк ФГОС Задание 352
Задание 352
\[\boxed{\text{352\ (352).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[\left\{ \begin{matrix} y = x^{2}\text{\ \ \ \ \ \ \ \ } \\ y = 4x - 4 \\ \end{matrix} \right.\ \]
\[x^{2} = 4x - 4\]
\[x^{2} - 4x + 4 = 0\]
\[(x - 2)^{2} = 0\]
\[x - 2 = 0\]
\[x = 2.\]
\[y = 2^{2} = 4.\]
\[y = x^{2}\]
| \[x\] | \[1\] | \[2\] | \[3\] | \[- 1\] | \[- 2\] |
|---|---|---|---|---|---|
| \[y\] | \[1\] | \[4\] | \[9\] | \[1\] | \[4\] |
\[y = 4x - 4\]
| \[x\] | \[0\] | \[1\] |
|---|---|---|
| \[y\] | \[- 4\] | \[0\] |
\[Ответ:(2;4).\]
\[\boxed{\text{352.}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[1)y = \frac{9x - 18}{x^{2} - 2x}\]
\[\frac{9x - 18}{x^{2} - 2x} = \frac{9 \cdot (x - 2)}{x(x - 2)} = \frac{9}{x}\]
\[y = \frac{9}{x};\ \ при\ x \neq 2\]
| \[x\] | \[2\] | \[4,5\] | \[3\] | \[- 2\] | \[- 4,5\] | \[- 3\] |
|---|---|---|---|---|---|---|
| \[y\] | \[4,5\] | \[2\] | \[3\] | \[- 4,5\] | \[- 2\] | \[- 3\] |
\[При\ a \neq 4,5;a \neq 0.\]
\[2)\ y = \frac{5x^{2} - 5}{x - x^{3}}\]
\[\frac{5x^{2} - 5}{x - x^{3}} = \frac{5\left( x^{2} - 1 \right)}{x\left( 1 - x^{2} \right)} = - \frac{5}{x}\]
\[y = - \frac{5}{x};\ \ при\ x \neq 1;\ \ x \neq - 1\]
| \[x\] | \[1\] | \[2\] | \[5\] | \[- 1\] | \[- 2\] | \[- 5\] |
|---|---|---|---|---|---|---|
| \[y\] | \[- 5\] | \[- 2,5\] | \[- 1\] | \[5\] | \[2,5\] | \[1\] |
\[При\ a \neq \pm 5;\ \ a \neq 0.\]
