Решебник по алгебре 8 класс Мерзляк Задание 31

\[\boxed{\text{31\ (31).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Пояснение.

Решение.

\[1)\ \frac{3x}{21y} = \frac{x}{7y}\]

\[2)\ \frac{5x^{2}}{6x} = \frac{5x}{6}\]

\[3)\ \frac{5c^{4}}{10c^{5}} = \frac{1}{2c}\]

\[4)\ \frac{2m^{4}}{m^{3}} = 2m\]

\[5)\ \frac{16ab^{4}}{40ab^{2}} = \frac{2b^{2}}{5}\]

\[6)\ \frac{63x^{5}y^{4}}{42x^{4}y^{5}} = \frac{9x}{6y} = \frac{3x}{2y}\]

\[7)\ \frac{12a^{8}}{- 42a^{2}} = - \frac{2a^{6}}{7}\]

\[8)\ \frac{- 13a^{5}b^{5}}{26a^{4}b^{3}} = - \frac{ab^{2}}{2}\]

\[\boxed{\text{32\ (32).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[1)\ \frac{- a}{- b} = \frac{a}{b}\]

\[2) - \frac{- a}{b} = \frac{a}{b}\]

\[3) - \frac{a}{- b} = \frac{a}{b}\]

\[4) - \frac{- a}{- b} = - \frac{a}{b}\]