\[\boxed{\mathbf{1076}\mathbf{\text{.\ }}Еуроки\ - \ ДЗ\ без\ мороки}\]
\[= \frac{1}{3} \cdot \left( \frac{1}{a} - \frac{1}{a + 12} \right) =\]
\[= \frac{a + 12 - a}{3a \cdot (a + 12)} = \frac{4}{a \cdot (a + 12)}\]