Решебник по алгебре 8 класс Мерзляк ФГОС Задание 1067

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\[1)\ \frac{7a}{22} + \frac{4a}{22} = \frac{11a}{22} = \frac{a}{2}\]

\[2)\frac{8x}{3y} - \frac{5x}{3y} = \frac{3x}{3y} = \frac{x}{y}\]

\[3)\ \frac{7x - 2y}{15p} + \frac{3x + 7y}{15p} =\]

\[= \frac{7x - 2y + 3x + 7y}{15p} =\]

\[= \frac{10x + 5y}{15p} = \frac{2x + y}{3p}\]

\[4)\ \frac{x + y}{9p} - \frac{x}{9p} = \frac{x + y - x}{9p} = \frac{y}{9p}\]

\[5)\frac{a}{8} - \frac{a - b}{8} = \frac{a - a + b}{8} = \frac{b}{8}\]

\[6)\ \frac{7p - 17}{5k} + \frac{7 - 2p}{5k} =\]

\[= \frac{7p - 17 + 7 - 2p}{5k} = \frac{5p - 10}{5k} =\]

\[= \frac{p - 2}{k}\]

\[7)\ \frac{6a^{2} - 4a}{15a} - \frac{a^{2} + a}{15a} =\]

\[= \frac{6a^{2} - 4a - a^{2} - a}{15a} =\]

\[= \frac{5a^{2} - 5a}{15a} = \frac{5a(a - 1)}{15a} = \frac{a - 1}{3}\]

\[8)\ \frac{x - y}{8} + \frac{x + y}{8} =\]

\[= \frac{x - y + x + y}{8} = \frac{2x}{8} = \frac{x}{4}\]

\[9)\ \frac{10x - 6}{x} - \frac{4x + 11}{x} =\]

\[= \frac{10x - 6 - 4x - 11}{x} = \frac{6x - 17}{x}\]