Решебник по алгебре 8 класс Макарычев ФГОС Задание 1186

\[\boxed{\text{1186.\ }\text{еуроки}\text{-}\text{ответы}\text{\ }\text{на}\text{\ }\text{пятёрку}}\]

\[\textbf{а)}\ 3x^{- 5} = 3 \cdot \frac{1}{x^{5}} = \frac{3}{x^{5}}\]

\[\textbf{б)}\ x^{- 4}y = \frac{1}{x^{4}} \cdot y = \frac{y}{x^{4}}\]

\[\textbf{в)}\ 5ab^{- 7} = 5a \cdot \frac{1}{b^{7}} = \frac{5a}{b^{7}}\]

\[\textbf{г)}\ 5\left( \text{ab} \right)^{- 7} = 5 \cdot \frac{1}{\left( \text{ab} \right)^{7}} = \frac{5}{\left( \text{ab} \right)^{7}}\]

\[\textbf{д)}\ x^{- 1}c^{- 3} = \frac{1}{x} \cdot \frac{1}{c^{3}} = \frac{1}{xc^{3}}\]

\[\textbf{е)} - 9yz^{- 8} = - 9y \cdot \frac{1}{z^{8}} = - \frac{9y}{z^{8}}\]

\[\textbf{ж)}\ 2 \cdot (x + y)^{- 4} =\]

\[= 2 \cdot \frac{1}{(x + y)^{4}} = \frac{2}{(x + y)^{4}}\]

\[\textbf{з)}\ 10x^{- 1}(x - y)^{- 3} = 10 \cdot \frac{1}{x} \cdot\]

\[\cdot \frac{1}{(x - y)³} = \frac{10}{x(x - y)³}\]