Решебник по алгебре 7 класс Мерзляк ФГОС Задание 852

 

\[\boxed{\text{852\ (852).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[1)\ y( - 4) = - 2 \cdot ( - 4) + 5 =\]

\[= 8 + 5 = 13\]

\[y(3,5) = - 2 \cdot 3,5 + 5 =\]

\[= - 7 + 5 = - 2\]

\[y(0) = 0 + 5 = 5\]

\[2)\ при\ y = 9:\ \ \]

\[- 2x + 5 = 9\]

\[- 2x = 4\ \]

\[x = - 2.\]

\[при\ y = - 5:\ \]

\[\ - 2x + 5 = - 5\ \]

\[- 2x = - 10\ \]

\[\ x = 5.\]

\[y = 0:\ \]

\[\ - 2x + 5 = 0\ \]

\[- 2x = - 5\]

\[\ x = 2,5.\]

\[\boxed{\text{852.\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[1)\ 4a³ - 4b^{3} = 4 \cdot \left( a^{3} - b^{3} \right) =\]

\[= 4 \cdot (a - b)(a^{2} + \text{ab} + b^{2})\]

\[2)\ 2m³ - 16 = 2 \cdot \left( m^{3} - 8 \right) =\]

\[= 2 \cdot (m - 2)(m^{2} + 2m + 4)\]

\[3)\ 7 + 7b³ = 7 \cdot \left( 1 + b^{3} \right) =\]

\[= 7 \cdot (1 + b)(1 - b + b^{2})\]

\[4) - x^{4} + 27x = x\left( 27 - x^{3} \right) =\]

\[= x(3 - x)(9 + 3x + x^{2})\]

\[5)\ 2a^{4} - 250a =\]

\[= 2a\left( a^{3} - 125 \right) =\]

\[= 2a(a - 5)(a^{2} + 5a + 25)\]

\[6)\ 9a^{5} - 9a^{2} = 9a^{2}\left( a^{3} - 1 \right) =\]

\[= 9a²(a - 1)(a^{2} + a + 1)\]